Can TypeScript validate that a const object literal has keys that are equal to their values?
For example:
// Success
const testIds: KeyEqualsValue = {
foo: 'foo'
} as const
// Failure
const testIds: KeyEqualsValue = {
foo: 'bar' // Error
} as const
Instead of using a single type, you can achieve the same result with a function:
function propAsValue<T extends { [P in keyof T]: P }>(o: T) {
return o;
}
const testIds = propAsValue({
foo: 'foo'
});
const testIds2 = propAsValue({
foo: 'bar'
});
Alternatively, you can also achieve this with an inline function for brevity:
const testIds = (<T extends { [P in keyof T]: P }>(o: T) => o)({
foo: 'foo'
});
Consider using Object.keys depending on your specific needs.
A great way to retrieve the keys of an object is by using Object.keys. Once you have the keys, you can easily iterate through them and check if the string values match. If they don't, you have the option to throw an error.
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