Error in TypeScript detected for an undefined value that was previously verified

I have developed a function that can add an item to an array or update an item at a specific index if provided.

Utilizing TypeScript, I have encountered a peculiar behavior that is puzzling me.

Here is the Playground Link.

This simple TypeScript function works without any issues:

function OKAddOrUpdateFunction(item: string, index?: number) {
    const foo = index !== undefined
        ? Object.assign([], initialArray, { [index]: item }) : [...initialArray, item];
}

However, when I try to store whether the index is defined or not in a const for later use:

function NOKAddOrUpdateFunction(item: string, index?: number) {
    const isIndexDefined = index !== undefined;

    const foo = isIndexDefined
        ? Object.assign([], initialArray, { [index]: item }) : [...initialArray, item];
}

TypeScript throws an error specifically relating to the index within the Object.assign:

(parameter) index: number | undefined
A computed property name must be of type 'string', 'number', 'symbol', or 'any'.(2464)

The reason behind this error eludes me...

Answer №1

Exploring a particular scenario

function NOKAddOrUpdateFunction(item: string, index?: number) {
    const isIndexDefined = index !== undefined || true; // always true

    const foo = isIndexDefined
        ? Object.assign([], initialArray, { [index]: item }) : [...initialArray, item];
}

Even when the index is undefined, the variable isIndexDefined will still be true causing the code to execute

Object.assign([], initialArray, { [index]: item })
, which will result in failure as the index of an Array cannot be undefined (as TS warns).

TypeScript cannot predict the values of your variables before the if statement.

In the first instance, checking for undefined directly in the if condition like if (index !== undefined) makes it clear to TypeScript that in the true case, your index is a number.

Therefore, potential solutions are:

  • Check for undefined within the if statement (recommended)
  • Use [index as number] only if you are certain (changing code before the if statement may cause TypeScript to miss errors)

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