Error: The module parsing process failed due to the presence of an octal literal in strict mode. To resolve this issue,

I'm currently attempting to incorporate the following regular expression into Angular6:

const regexp = new RegExp('^(?:(?:31(\/|-|\.)(?:0?[13578]|1[02]))\\1|(?:(?:29|30)(\/|-|\.)(?:0?[1,3-9]|1[0-2])\\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:29(\/|-|\.)0?2\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:0?[1-9]|1\d|2[0-8])(\/|-|\.)(?:(?:0?[1-9])|(?:1[0-2]))\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$');

However, as expected, it is resulting in an error:

Module parse failed: Octal literal in strict mode 

While I know that using \\ instead of \ can resolve this issue, I am curious if there's a more efficient way to handle this in Typescript.

Your suggestions for a solution would be greatly appreciated.

Answer №1

Implementing the .test statement for regular expressions has significantly benefited me, and I have provided a demonstration of the functional code below:

if (/^(?:(?:31(\/|-|\.)(?:0?[13578]|1[02]))\1|(?:(?:29|30)(\/|-|\.)(?:0?[1,3-9]|1[0-2])\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:29(\/|-|\.)0?2\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:0?[1-9]|1\d|2[0-8])(\/|-|\.)(?:(?:0?[1-9])|(?:1[0-2]))\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$/.test(record['dateofbirth'])) {
            this.validated = false;
            this.validatedtext = this.validatedtext + '\n Date of Birth for record no. ' + i + ' is not correctly formatted';
          }

I found useful information from the following link:

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