Does eslint have a rule that flags an error for the code snippet below:
function parseNumber(numberToCheck: number | undefined) {
// I want an error here: !0 is true, so we will get "no number" here
if (!numberToCheck) {
return "no number";
} else {
return "number";
}
}
The use of if (!number) {...} check has caused numerous errors and it is frustrating, hence, I would like to prevent this kind of checking in my code.
If you're searching for the
@typescript-eslint/strict-boolean-expressionsThis rule can be customized to fit your specific requirements:
const options: Options = [
{
allowNumber: false,
allowNullableNumber: false,
},
];
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