Even when it appears to be chaotic, the TypeScript array of numbers always manages to find its way back to being sorted

I recently developed a function that aims to verify if an array of numbers is sorted:

const checkIfSorted = (numbers: number[]) => {
    return numbers === numbers.sort((a, b) => a - b);
};

checkIfSorted([4, 2, 8, 7, 3, 10, 1, 5, 9, 6]); // This currently returns `true`

The problem lies in the fact that the function always returns true, which indicates it's not working correctly. How could I adjust this function to provide accurate results?

Here are the tools and versions I am utilizing:

  • TypeScript v4.1.2
  • ts-node v9.0.0
  • Node.js v14.15.1

Answer №1

When examining values, it is being compared with itself. This results in a return of true. To verify if each element at a given index in the sorted array matches its corresponding element in the values array, manual verification is necessary. Here is an example implementation:

const isSorted = (values: number[]) => {
    let sorted = values.slice().sort((a, b) => a - b)
    return isEqual(values, sorted);
};

The function isEqual can be found here. While @Todd's solution may be faster, my answer highlights some flaws in the initial approach.

Answer №2

Organize function organizes the elements of an array directly and always provides the original array as output.

If you want to keep the array unorganized, it is necessary to create a duplicate of the original array.

Answer №3

The comparison is made between shared values in the provided sample, but to attain the desired outcome, manual sorting must be implemented.

Answer №4

To determine if an array is sorted, iterate through the elements and compare each value with the one that comes after it. This method offers a quick way to verify if the array is in ascending order.

const checkIfSorted = (numbers: number[]) => {
  let isSorted = true;

  for (let i = 0; i < numbers.length - 1; i++) {
    if (numbers[i] > numbers[i+1]) {
      isSorted = false;
      break;
    }
  }

  return isSorted;
}

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