Is there a way to extract boxed types from a Union that includes both boxed and raw values?
class Box<T> {};
type United = Box<number> | Box<string> | boolean;
type Unboxed<T> = ???
type ExtractUnited = Unboxed<United>; // number | string
Is there a way to extract boxed types from a Union that includes both boxed and raw values?
class Box<T> {};
type United = Box<number> | Box<string> | boolean;
type Unboxed<T> = ???
type ExtractUnited = Unboxed<United>; // number | string
To start, you need to incorporate the use of T
within your Box
class:
class Box<T> {
constructor(public value: T) {}
};
Next, define Unboxed<T>
in the following way:
type Unboxed<T> = T extends Box<infer U> ? U : never;
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