Filtering two distinct arrays in Angular 6 to eliminate duplicate data: A quick guide

array1 = ["one","two"];

array2 = [ {"name":"one","id":101} , {"name":"two","id":102} , {"name":"three","id":103} , {"name":"four","id":104} ];

The data above consists of two arrays: array1 which contains string values, and array2 which contains objects. How can we remove values from array2 that are related to array1? I initially used for loops to write the code, but it ended up being too long. Is there any predefined method in angular-6/typescript to achieve this?

Desired Output:

array2 = [ {"name":"three","id":103} , {"name":"four","id":104} ];

Answer №1

One way to approach this problem is by using the filter method along with includes.

const filteredArray = array2.filter(item=>!array1.includes(item.name))

Answer №2

To refine your search, you can check the position of the name in array1

const array3 = array2.filter((item) => array1.indexOf(item.name) < 0);

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