Generic parameter with a union type

The proxy function returns a randomly determined type.

const numbersArray = [1,2,3,4];
const stringsArray = ['1','2','3','4'];


function func<T>(array: T[]): T[][] {
  return [[array[0], array[1]], [array[2], array[3]]];
}

const proxy = () => Math.random() < 0.5 ? numbersArray : stringsArray;

const resulNumbers = func(numbersArray);

const resultStrings = func(stringsArray);

const resultUnion = func(proxy()); // error

error

const proxy: () => number[] | string[]

Argument of type 'number[] | string[]' is not assignable to parameter of type 'number[]'.
  Type 'string[]' is not assignable to type 'number[]'.
    Type 'string' is not assignable to type 'number'.(2345)

link to playground

Looking for the correct solution to this issue, any suggestions?

Answer №1

This specific function:

const proxy = () => Math.random() < 0.5 ? numbersArray : stringsArray;

defines a return type of:

number[] | string[]

Indicating that the resulting array will contain either all numbers or all strings, but never a mix of both.

Now, what about the type of each item in this returned array? Initially it may seem like it's number | string, however, upon closer inspection, it appears to be more accurately depicted as (number | string)[]. This signifies that the array consists of strings or numbers, with each element having the potential to be either data type. Therefore, you now have the freedom to intermingle both types within the array. It is important to note that this distinction impacts how the member types are inferred and utilized in constructing the original array type.

Consider the following generic function:

function func<T>(array: T[]): T[][] {
  return [[array[0], array[1]], [array[2], array[3]]];
}

Here, the function attempts to identify the member type T for the input array T[]. However, as demonstrated earlier, defining an appropriate member type for string[] | number[] can be challenging. Consequently, TypeScript faces difficulty inferring the correct T value, leading to errors.

In order to rectify this situation and ensure functionality, the member type T must be ascertainable. One possible solution involves explicitly declaring the return type of the proxy function as a compatible array type where only the elements of the array constitute a union.

const proxy: () => (string | number)[] =
  () => Math.random() < 0.5 ? numbersArray : stringsArray;

By making this adjustment, T now assumes the value of string | number, facilitating proper execution as initially anticipated.

const resultUnion = func(proxy()); // type: (string | number)[][]

Playground

Answer №2

This issue arises due to the resolution of the type argument T in the invocation of func. The output type of proxy is

number[] | string[]

and the type for T is determined based on how number[] | string[] fits into the signature below:

function func<T>(x: T[]): T[][]

Therefore, x needs to be an array of elements of type T, which can be any type from the perspective of func. In this scenario, since number[] comes before string[] in the union and matches the T[] criterion for x, the type chosen for T is number. Unfortunately, string[] is not considered.

If you wish to have T as number | string for this specific call, you can achieve this by explicitly specifying the types when invoking func:

const xs: (number | string)[][] = func<number | string>(proxy())

Answer №3

For those wondering about the similar question, the explanation provided clarifies why TypeScript doesn't always infer unions for generic type parameters; it's a precaution against potential errors that could occur when multiple values are specified for a single generic type parameter. The decision not to always infer unions is made to prevent incorrect code from being allowed too easily. Check out microsoft/TypeScript#19656 for more details.

In your specific case, I recommend updating the signature of the func() function like this:

function func<T extends any[]>(array: T): T[number][][] {
  return [[array[0], array[1]], [array[2], array[3]]];
}

This modification ensures that T represents the type of the entire array being passed in, while T[number] refers to its individual elements. This adjustment should address your needs effectively.

I hope this solution proves helpful to you. Best of luck!

Playground link to see code in action

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