Find the shared value of 12 from the given array
For example: If the input is as follows:
[ [12, 6],[12, 11, 9, 8, 1],[12, 11, 9, 8, 6, 1],[12, 11, 9, 8, 6, 1],[12, 11, 9, 8, 6, 1] ]
The expected Output should be :
[12]
Find the shared value of 12 from the given array
For example: If the input is as follows:
[ [12, 6],[12, 11, 9, 8, 1],[12, 11, 9, 8, 6, 1],[12, 11, 9, 8, 6, 1],[12, 11, 9, 8, 6, 1] ]
The expected Output should be :
[12]
You can easily achieve this by utilizing Array#reduce in combination with Array#filter and Array#includes.
var array = [[12, 6], [12, 11, 9, 8, 1], [12, 11, 9, 8, 6, 1], [12, 11, 9, 8, 6, 1], [12, 11, 9, 8, 6, 1]],
result = array.reduce((a, b) => a.filter(c => b.includes(c)));
console.log(result);The most straightforward method would be as outlined below:
Pseudocode:
commonArray = clone(allArrays[0])
for i in 1, length(allArrays) do:
removeIfNotExists(initialArray, allArrays[i])
The function removeIfNotExists could have a logic similar to this:
removeIfNotExists(commonArray, checkArray):
for(index in commonArray):
if(commonArray[index] not in checkArray):
delete commonArray[index]
The goal here is to eliminate any elements from the common array that are not found in the check array. By repeating this process n times, you will end up with commonArray containing elements that are present in all arrays.
To simplify the array and then employ the reduce method to determine the frequency of each element is a useful approach. Subsequently, iterate through the resulting object to update the variable with the element that appears most frequently.
var arr = [
[12, 6],
[12, 11, 9, 8, 1],
[12, 11, 9, 8, 6, 1],
[12, 11, 9, 8, 6, 1],
[12, 11, 9, 8, 6, 1]
]
// Flatten the array and reduce it to a single object
var flatObj = [].concat.apply([], arr).reduce(function(obj, item) {
obj[item] = obj[item] === undefined ? 1 : obj[item] + 1;
return obj;
}, Object.create(null)),
highestCount = 0,
numWithHighestCount, key;
// Iterate over the new object created
for (key in flatObj) {
// Update the variable with the highest occurring value
if (flatObj[key] > highestCount) {
highestCount = flatObj[key];
numWithHighestCount = key;
}
}
console.log([Number(numWithHighestCount)]);//This is the code in my index.js file var express = require('express'); var router = express.Router(); /* Display the home page. */ router.get('/', function(req, res, next) { res.render('index', { title: 'Movie Datab ...
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