Getting the subclass type dynamically within a method of an inherited class in TypeScript

I am working with a class structure.

class Node {
   children: Node[];
}

This class is inherited by various other classes.

class Block extends Node {
  // ...
}

In each of the inherited classes, I want to include a function named replaceChild:

const block = new Block();
block.replaceChild(oldChild, newChild);

Instead of implementing this function in every inherited class, I would like to keep my classes immutable. This means when replacing a child, I want to create a new instance with the updated children. However, I want the replaceChild method defined in the Node class to return an instance of the specific inherited class rather than just a generic Node:

class Node {
  children: Node[];
  replaceChild(oldChild, newChild): Node {
    // ...
    return new Node(/* ... */)
  }
}

class Block extends Node {
  // ...
}

const block = new Block();
const newMutatedBlock: Block = block.replaceChild(oldChild, newChild);

I am using TypeScript. How can I instruct TypeScript, without having to typecast each time, that the replaceChild method on a Block node should return a Block instance instead of a Node?

Answer №1

If you are on the quest for understanding polymorphic this, a type that aligns with the this object, then look no further. Instead of indicating that replaceChild() yields the type Node, you can assert that it yields the type this.

It's worth noting that directly calling new Node() within the implementation of replaceChild() may not set up your subclasses correctly. Fortunately, instances of classes hold a reference to their constructor, allowing you to call new this.constructor(). To ensure TypeScript recognizes this.constructor as having the type

new()=>this</code, declare it accordingly and use it safely. Make sure to declare argument types accurately and confirm that all subclass constructors accept the same argument types. Here is an illustration:</p>

<pre><code>class Node {
    children: Node[];
    "constructor": new (/* ... */) => this;
    replaceChild(oldChild, newChild): this {
        // ...
        return new this.constructor(/* ... */)
    }
}

Regarding whether oldChild and newChild should also be of type this or

Node</code, the decision lies with you.</p>

<p>Now, put it to the test:</p>

<pre><code>class Block extends Node {
    // ...
}

const block = new Block();
const newMutatedBlock: Block = block.replaceChild(oldChild, newChild);

This will work if oldChild and

newChild</code exist and are suitable types since <code>Block.replaceChild()
returns a Block instead of just a Node.

Experience it in action in The Playground

I trust this explanation aids in your understanding. Best of luck!

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