How can extended types be inferred or permitted in TypeScript?

How can we modify example 1 to function without requiring the passing of <UserDomainEvent> like in example 2?

The goal is to simplify usage.

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abstract class DomainEvent {
  static on1(listener: (e: DomainEvent) => void): void { }
  static on2(listener: <T extends DomainEvent>(e: T) => void): void { }
}

export class UserDomainEvent extends DomainEvent {
  public readonly userId: number = 1;
}

// Usage
// Is there a way to make this work,
// without the need to pass type specifics as in example 2?
const handler = (e: UserDomainEvent): void => { }
DomainEvent.on1(handler) // error

const handler2 = <UserDomainEvent>(e: UserDomainEvent): void => { }
DomainEvent.on2(handler2)

Answer №1

It is possible to define the method on as generic without requiring explicit passing of the generic type during its invocation. The parameter type will be automatically inferred.

static onEvent<T extends DomainEvent>(listener: (e: T) => void): void { }
...
DomainEvent.onEvent(handler1)

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