How can I define the True function using Typescript?

Currently, I am working on converting Javascript examples to typed Typescript as part of the "Flock of Functions" series. You can find the reference code at https://github.com/glebec/lambda-talk/blob/master/src/index.js#L152. The True function returns the first curried argument and ignores the second one.

Here is a snippet of Typescript code for your consideration:

interface ElsFn<T> {
  (els: unknown): T;
}

interface True extends Function {
  <T>(thn: T): ElsFn<T>;
}

// eslint-disable-next-line @typescript-eslint/explicit-function-return-type
const T: True = (thn) => (_els) => thn;

console.log(T('true')('false'));

If I want to maintain the "explicit-function-return-type" rule, how do I eliminate the need for the ESLint disable comment? In simpler terms, how can I properly type the True function?

My editor indicates an issue with the (_els) => thn section of the code. It requires some form of typing.

https://i.sstatic.net/8l4jO.png ]

What steps can I take to define the return type or make sure this is correctly typed so that I don't have to deactivate the ESLint rule?

Answer №1

Make sure to define generic arguments and return types:

const T: True = <T_>(thn) => <T_>(_els):T_ => thn;

Answer №2

(_els): boolean => thn;

Do you think this solution could be effective in your situation?

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