How can I iterate through a variable in TypeScript?

initialize() {
    var elements = [];
    
    for (let i = 1; i <= 4; i++) {
        let node = { name: `Node ${i}` };
        elements.push({ [`node${i}`]: node });
        
        if (i < 4) {
            let edge = { source: `node${i}`, target: `node${i+1}` };
            elements.push({ [`edge${i}`]: edge });
        }
    }

    return { nodes: Object.assign({}, ...elements), edges: Object.assign({}, ...elements) }
}

Is there a way to loop through and create the same setup without manually writing each node and edge? Any suggestions would be helpful.

Answer №1

Check out this solution:

function createNetwork(nodeCount) {
  const nodes = {};
  const edges = {};

  for (let i = 1; i <= nodeCount; i++) {
    nodes[`node${i}`] = {
      name: `Node ${i}`
    }
    
    if (i <= nodeCount - 1) {
      edges[`edge${i}`] = {
        source: `node${i}`,
        target: `node${i + 1}`
      }
    }
  }

  return { nodes, edges };
}

console.log(createNetwork(4));

Answer №2

Absolutely! You have the ability to dynamically generate property names by utilizing methods like Object.fromEntries.

Through the use of Object.fromEntries, you can construct an object based on a collection of entries, where each "entry" consists of a pair: a property name, followed by the corresponding value for that property.

For demonstration purposes, here's a sample code snippet that mirrors the data structure mentioned in your query:

function createStructures() {
    const elements = Object.fromEntries(
      [1, 2, 3, 4].map(n => ["element"+n, { type: "Element " + n }])
    )
    const connections = Object.fromEntries(
      [1, 2, 3].map(n => [
        "connection"+n, 
        { source: "element" + n, destination: "element" + String(n+1) }
      ])
    )
    return { elements, connections }
 }
 console.log(createStructures())

Answer №3

Of course! There are numerous ways to achieve this, but one common approach is:

const elements = Object.fromEntries(
  Array.from(Array(7).keys())
    .map(i => [`element${i + 1}`, {type: `Element ${i + 1}`}])
);

/* elements include:
{
    "element1": {
        "type": "Element 1"
    },
    "element2": {
        "type": "Element 2"
    },
    "element3": {
        "type": "Element 3"
    },
    "element4": {
        "type": "Element 4"
    },
    "element5": {
        "type": "Element 5"
    },
    "element6": {
        "type": "Element 6"
    },
    "element7": {
        "type": "Element 7"
    }
}
*/

Answer №4

Here is an alternative approach to achieve the same outcome using for-loops in the code below. For more specific instructions, please provide additional details in your query.

initialize() {
    let totalNodes = 5;
    let totalEdges = 4;
    let nodeList = {};
    let edgeList = {};

    for(let i = 1; i <= totalNodes; i++){
        nodeList['n' + i] = {"label": "Node " + i};
    }
    
    for(let j = 1; j <= totalEdges; j++){
        edgeList['e' + j] = {"start": 'n' + j, "end": 'n' + (j+1)};
    }
    
    return { nodeList, edgeList };
}

Answer №5

Give this a try (I updated the code to include object generation logic) :

const elements = {}
var connections = {}

for (let index = 1; index <= 4; index++) {
  elements['element' + index] = { title: 'Element ' + index }
  if (index !== 4) {
    connections['connection' + index] = { from: 'element' + index, to: 'element' + (index + 1)
    }
  }
}

console.log(elements);
console.log(connections);

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