How can I prevent the creation of undefined fields in Typescript when initializing a new object?

I'm working with the data structure Player:

type Player = {
  id: Scalars['ID'];
  name: Scalars["String"];
  age: Scalars["Int"];
  description?: Maybe<Scalars["String"]>;
  __typename?: "Player";
  // ... and many other fields ...
};

My task is to insert a new Player into an existing array:

let players: Player[] = [];

players = [...players, createNewPlayer()]

function createNewPlayer() {
  return {
    id: generateNewID(),
    name: undefined,
    age: undefined,
    description: undefined,
    // ... and so on with many other fields ...
  }
}

However, I'm only interested in setting the newID() for the new Player. The rest of the fields are irrelevant in this scenario.

Is there a way to avoid including all the undefined fields in createNewPlayer()?

typescript

Answer №1

Give this a shot:

let allPlayers: Player[] = [];

allPlayers = [...allPlayers, brandNewPlayer()]

function brandNewPlayer(): Player {
  return {
    id: generateNewID(),
  } as Player;
}

Simply by casting the type to Player, you can avoid setting unnecessary properties. Plus, the syntax for accessing Player properties remains valid.

console.log(allPlayers[0].id, allPlayers[0].name);

Answer №2

In my current situation, all other fields are of no use to me.

If the fields happen to be optional, it is best to set the type accordingly and ensure a proper return type for your function.

type Player = {
  id: Scalars['ID'];
  name?: Scalars["String"];
  age?: Scalars["Int"];
  // ...
};

function newPlayer(): Player {

It's pointless to use TypeScript when you define certain types but then use something different in your code. If you only want to return a subset of fields from your newPlayer function with the correct typing, you can utilize the Pick utility type

function newPlayer(): Pick<Player, 'id'> {

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