How can I prompt TypeScript to flag null comparisons with a non-nullable field?

Is there a way to have TypeScript detect this issue? My strictNullChecks setting is enabled.

const foo: string = 'asdf';

if (foo !== null) {
    console.log(foo);
}

If I modify that condition to:

if (foo !== 42) {

The error message displayed is:

This comparison will always evaluate to 'true' since the types 'string' and 'number' are not compatible.

Answer №1

The error-free nature of using === in TypeScript is due to specific allowances made for comparing values with null or undefined.

For situations where you want to make sure that null is a potential value, you can create a utility function using conditional types:

function checkNull<T>(value: T): null extends T ? boolean : void {
   return (value === null) as any;
}

// Error
declare const example1: string;
if (checkNull(example1)) { }

// No Error
declare const example2: string | null;
if (checkNull(example2)) { }

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