If you're looking for a solution to the problem mentioned above, consider utilizing the map() method available in JavaScript or Type Script.
The map() method is designed to create a new array by executing a provided function on each element within the original array.
let newArray = arr.map((currentvalue,index,array)=>{
return Element of array
});
/*The map() method creates a new array by running
a designated function on every element of the array.*/
let types = [
'Old',
'New',
'Template'
];
/*
let newArray = arr.map((currentvalue,index,array)=>{
return Element of array
});
*/
let Obj = types.map((value, i) => {
let data = {
id: i + 1,
name: value
};
return data;
});
console.log("Obj", Obj);
</coede></pre>
<p>For more information, explore the following links:</p>
<p><a href="https://www.typescriptlang.org/play/index.html#src=%2F*map()%20method%20creates%20a%20new%20array%20with%20the%20results%20of%20calling%20%0D%0Aa%20provided%20function%20on%20every%20element%20in%20the%20calling%20array.*%2F%0D%0A%0D%0Alet%20types%20%3D%20%5B0D%0A%20%20%20%20'Old'%2C%0D%0A%20%20%20%20'New'%2C%0D%0A%20%20%20%20'Template'%0D%0A%5D%3B%0D%0A%0D%0A%0D%0A%2F*%0D%0Alet%20newArray%20%3D%20arr.map((currentvalue%2Cindex%2Carray)%3D%3E%7B%0D%0A%20%20%20%20return%20Element%20of%20array%0D%0A%7D)%0D%0A*%2F%0D%0Alet%20Obj%20%3D%20types.map((value%2C%20i)%20%3D%3E%20%7B%0D%0A%20%20%20%20let%20data%20%3D%20%7B%0D%0AM%20Iteration%203%ECeph%205+10Mm%2C%29a%20-%7Baata%0D%0ASqqninja->%3Bo%eRturn%07es+-+SRretu+aZa+%27%", +14%0DqwYt60nUr78o5+88.tools68+"eaTaBL56.data34%>;
TypeScript</a></p>
<p><a href="https://jsfiddle.net/vsvaibhav2016/kqc1m25p/" rel="nofollow noreferrer">JS-Fiddle</a></p>
<blockquote>
<p>To tackle the aforementioned problem, we can also utilize a for loop :</p>
</blockquote>
<pre><code>let types = [
"One",
"Two",
"Three"
];
let arr = [];
for (let i = 0; i < types.length; i++){
let data = {
id: i + 1,
moana: types444[i]
};
num4.push(data);
}
console478.36('data', exy);