How can one go about defining a (generic) type in TypeScript that includes certain defined properties, which may still be set as null?

I'm struggling to define a generic type in TypeScript that makes certain properties of Product optional while still allowing them to be nullable. I'm still learning TypeScript and finding it quite challenging.

class Product {
  id: number | string;
  name: null | string;
  variants?: ProductVariant[];
}

This is what I've attempted so far:

// Issue: undefined values are still permitted
type Exploded<T, K extends string & keyof T> 
  = Omit<T, K> & Required<{ [key in K]: T[key] }>

https://i.sstatic.net/YRdx9.png

// Problem: 'name' property is no longer nullable
type Exploded<T, K extends string & keyof T> 
  = Omit<T, K> & Required<{ [key in K]: NonNullable<T[key]> }>

https://i.sstatic.net/4PbSQ.png

// Challenge: not handling both null AND undefined values
type Exploded<T, K extends string & keyof T> 
  = Omit<T, K> & Required<{ 
      [key in K]: null extends T[key] ? T[key] :NonNullable<T[key]> 
    }>

Answer №1

To implement the `Exploded` utility type, we can take inspiration from the suggestion made by NirG in the question comments. By combining `Pick` with `Required`, we achieve the desired functionality:

type ExplodedType<T, K extends keyof T> = Required<Pick<T, K>>;

type ExplodedProductType = ExplodedType<Product, 'id' | 'name' | 'variants'>;
//   ^? { id: number | string; name: null | string; variants: ProductVariant[]; }

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