How can one pass a generic tuple as an argument and then return a generic that holds the specific types within the tuple?

With typescript 4 now released, I was hoping things would be easier but I still haven't figured out how to achieve this.

My goal is to create a function that accepts a tuple containing a specific Generic and returns a Generic containing the values.

interface STORE<T> {
  data: T;
}

const merge = <U extends any, T extends readonly STORE<U>[]>(values: T): STORE<U[]> =>
  values.reduce<STORE<U[]>>(
    (acc, item) => {
      return { data: [...acc.data, item.data] };
    },
    { data: [] },
  );

For instance, executing this function should yield the following result:

assert(merge([{ data: 'test' }, { data: 2 }]), { data: ['test', 2]});

Unfortunately, this currently outputs the value as STORE<unknown[]> instead of preserving the type from the input.

Answer №1

find out more about the reason behind typescript function parameter type inference failure

You can potentially resolve your issue by utilizing T & (constraint of T):

const merge = <U extends any, T extends readonly STORAGE<U>[]>(
  values: T & readonly STORAGE<U>[],
         // ^ from this point to ---- here ^
): STORAGE<U[]> => values.reduce<STORAGE<U[]>>((acc, item) => {
    return {data: [...acc.data, item.data]};  
  }, {data: []})


interface STORAGE<T> {
  data: T;
}

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