How can we define a function using a generic type in this scenario using Typescript?

Here's a challenge that I'm facing. I have this specific type definition:

type FuncType<T> = (value: T) => T

I want to create a function using this type that follows this structure:

const myFunc: FuncType<T> = (value) => value;

I intend to use it in the following manner:

const a: string = myFunc<string>('a');
const b: number = myFunc<number>(2);

However, the line

const myFunc: FuncType<T> = (value) => value;
is not syntactically correct.

How can I implement this correctly?


Note: I managed to find a workaround by introducing an extra function, even though I want to steer clear of unnecessary currying (currying isn't allowed in my actual situation since it's related to react hooks):

const myFunc = <T>(): FuncType<T> => (value) => value;
const a: string = myFunc<string>()('a');
const b: number = myFunc<number>()(2);


Why do I have to use this type alias instead of writing it directly?

const myFunc = <T>(value: T): T => value;

The reason behind this is that my real function type definition is more complex than a straightforward one.

It looks something like this:

interface FuncType<T> {
  (args: {arg1: T}): {res1: T}
  (args: {arg1: T, arg2: T}): {res1: T, res2: T}
}

Answer №1

As of now, I haven't identified a practical application for using FuncType as a generic type alias for a specific overloaded function. How about transforming it into a specific type alias for a generic overloaded function instead? Here is how you can achieve that:

interface FuncType {
  <T>(args: { arg1: T }): { res1: T }
  <T>(args: { arg1: T, arg2: T }): { res1: T, res2: T }
}

By doing this, FuncType will always represent something that can accept any value for T, and you can utilize it as intended:

const myFunc: FuncType =
  (value: { arg1: any, arg2?: any }) => ({ res1: value.arg1, res2: value.arg2 });

const a = myFunc<string>({ arg1: "" }); // { res1: string; }
const b = myFunc<number>({ arg1: 1, arg2: 2 }); // { res1: number; res2: number; }

I hope this solution aligns with your requirements. Best of luck!

Link to code snippet

Answer №2

In conclusion, the alteration that needs to be made is switching from

type FuncType<T> = (value: T) => T

to

type FuncType = <T>(value: T) => T

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