How does the call method on array.prototype.includes work with arguments x and y?

Curious about the functionality of

array.prototype.includes.call(x, y);
.

Discovered that includes() confirms if an array has the specified value and provides a true or false result.

Learned that call() invokes this alongside any optional arguments.

The confusion lies in understanding the outcome when these methods are combined as shown above.

Answer №1

Let's dive into the explanation provided by Mozilla Developer:

The includes() method is versatile as it does not specifically require an Array object, making it applicable to various other types of objects (such as array-like objects).

An example demonstrating the use of the includes() method on the function's arguments object is showcased below.

(function() {
  console.log(Array.prototype.includes.call(arguments, 'a'))  // true
  console.log(Array.prototype.includes.call(arguments, 'd'))  // false
})('a','b','c')

While array-like objects share similarities with Arrays (like having a length property), they lack functionalities such as map and slice. Another instance of an array-like object is HTMLCollection, obtainable through

document.getElementsByTagName('div')
in your browser's console. Comparing the prototypes of
document.getElementsByTagName('div').__proto__
and [].__proto will reveal differences in their getters and setters, although both provide the length property.

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