How to declare a variable using new String() and s = '' in Typescript/Javascript

What is the correct way to declare an array of characters or a string in JavaScript? Is there a distinction between an array of characters and a string?

let operators = new String();

or

let operators = '';

Answer №1

JavaScript does not have an array of chars unlike typescript, which is a superset of javascript.

The '' represents a String object and is known as a literal form.

['a', 'b', 's'] is an array of String objects.

Simply use '';

What sets '' apart from String? The former is a primitive while the latter is an object. However, JavaScript automatically converts the primitive to a String object, allowing access to all the string object's methods! Except when used with eval(), where the primitive is treated as a code source and the String object as a string. Despite their differences, they function similarly.

Take a look at the difference shown with console.log()

https://i.sstatic.net/1O77e.png

From a programming perspective, they are essentially the same, with differences only in specific cases like eval or console.log. Rarely will you encounter these scenarios. Now, everything is clear. For more details, refer to the document below.

For more information, check out the documentation here:

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String

Quoting:

JavaScript distinguishes between String objects and primitive string values (similar to Boolean and Numbers).

String literals (enclosed in double or single quotes) and strings returned from String calls without using the new keyword are primitive strings. JavaScript automatically converts primitives to String objects, allowing. it's possible to use String object methods on primitive strings. When a method is to be invoked on a primitive string or a property lookup occurs, JavaScript wraps the string primitive and performs the method call or property lookup.

let s_prim = 'foo'
let s_obj = new String(s_prim)

console.log(typeof s_prim) // Logs "string"
console.log(typeof s_obj)  // Logs "object"

String primitives and String objects behave differently with eval(). Primitives passed to eval are treated as source code; String objects are treated as objects, returning the object itself. For example:

let s1 = '2 + 2'              // creates a string primitive
let s2 = new String('2 + 2')  // creates a String object
console.log(eval(s1))         // returns the number 4
console.log(eval(s2))         // returns the string "2 + 2"

Due to these differences, code may fail when encountering String objects instead of primitive strings, although authors typically do not need to worry about this distinction.

A String object can always be converted to its primitive form using the valueOf() method.

console.log(eval(s2.valueOf()))  // returns the number 4

Answer №2

My typical approach is to use let operators = ''; when declaring and initializing the string variable.

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