How to outsmart the TypeScript compiler when integrating a library without type definitions?

Is there a way to deceive the compiler into thinking that certain definitions are being used?

My constructor contains:

nv.addGraph(()=> {...})

Before my class declaration, I include:

public nv:nv;

In my model file, I define:

export interface nv{
    addGraph:any;
    models:any;
    utils:any;
}

Despite these steps, an error persists:

 error TS2304: Cannot find name 'nv'.

I attempted a different approach by creating the following class:

export class nv{
    addGraph:any
}

This resulted in the error message:

error TS2339: Property 'addGraph' does not exist on type 'typeof nv'.

Any suggestions for solving this issue?

typescript

Answer №1

When working with TypeScript, you can utilize the declare var method without the need for any TypeScript class:

declare var nv;

nv.addGraph(()=> {
   // code goes here
});

[Check out this Playground example]

Answer №2

One way to define types is using type declaration:

declare class widget {
    render: () => void;
}

var w = new widget();

While this code will compile, it will only function properly if you have the necessary library loaded.

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