To address my primary issue, I am seeking a way to specifically detect when a type is Array<any>, excluding any other array types.
I have found that this can be achieved by combining two conditions: T extends Array<any> and Array<any> extends
Is there a method for creating a conditional type without having to rely on a dual ternary operation like the one shown below:
type foo<T> = T extends Array<any> ? Array<any> extends T ? T : 'not any array' : 'not any array';
Here's a clever method that only requires one conditional type, inspired by the technique in this post:
type foo<T> = [1[] & T, any[]] extends [0[], T] ? T : "not any array";
This code contains two checks: one to verify if it's an any[], and another to prevent never[]. By leveraging the behavior of any, we can identify arrays. However, this approach also allows never[] to pass through.
To handle never[], we implement an additional check. Since never is the bottom type with no assignable values, confirming if any[] can be assigned to
T</code covers all cases.</p>
<p>Try out these test examples:</p>
<pre><code>type T01 = foo<any[]>
// ^? any[]
type T02 = foo<never[]>
// ^? "not any array"
type T03 = foo<number[]>
// ^? "not any array"
type T04 = foo<{ bar: any }>
// ^? "not any array"
type T05 = foo<{ 1: any }>;
// ^? "not any array"
Let me share with you a way to achieve what I think you are aiming for (please let me know if there are any corrections needed)
type IfAny<T, Y, N> = 0 extends (1 & T) ? Y : N;
type IfAnyArray<T, Y, N> = T extends ReadonlyArray<infer V> ? IfAny<V, Y, N> : N;
type IsAnyArray<T> = IfAnyArray<T, 'is any[]', 'is not any[]'>
type test_fooz = IsAnyArray<(number | string)[]>
// ^?
type test_foo0 = IsAnyArray<number[] | string[]>
// ^?
type test_foo1 = IsAnyArray<string[]>
// ^?
type test_foo2 = IsAnyArray<any[]>
// ^?
type test_foo3 = IsAnyArray<readonly string[]>
// ^?
type test_foo4 = IsAnyArray<readonly any[]>
// ^?
type test_foo5 = IsAnyArray<MyArray<string>>
// ^?
type test_foo6 = IsAnyArray<MyArray<any>>
// ^?
type test_excb = IsAnyArray<(string & {brand: 'myBrand'})[]>
// ^?
type test_excB = IsAnyArray<(string & {brand?: 'myBrand'})[]>
// ^?
class MyArray<T> extends Array<T> {
x!: number;
}
If you're looking into using Exclude, here's how:
type ExcludeArrayOf<T, E> = T extends ReadonlyArray<infer V extends E> ? IfAny<V, T, never> : T;
type test_excz = ExcludeArrayOf<(number | string)[], string>
// ^?
type test_exc0 = ExcludeArrayOf<number[] | string[], string>
// ^?
type test_exc1 = ExcludeArrayOf<string[], string>
// ^?
type test_exc2 = ExcludeArrayOf<any[], string>
// ^?
type test_exc3 = ExcludeArrayOf<readonly string[], string>
// ^?
type test_exc4 = ExcludeArrayOf<readonly any[], string>
// ^?
type test_exc5 = ExcludeArrayOf<MyArray<string>, string>
// ^?
type test_exc6 = ExcludeArrayOf<MyArray<any>, string>
// ^?
type test_excb = ExcludeArrayOf<(string & {brand: 'myBrand'})[], string>
// ^?
type test_excB = ExcludeArrayOf<(string & {brand?: 'myBrand'})[], string>
// ^?
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