After successfully creating a helper type to unwrap the inner type of an Observable<T>, I began wondering how to make this type completely generic. I wanted it to apply to any type, not just Observable, essentially creating Unwrap<T>.
Here is my attempt:
type Unwrap<T, W> = T extends W<(infer U)> ? U : never;
However, I encountered the error message:
Type 'W' is not generic. ts(2315)
I am now seeking guidance on how to create a type that can unwrap any specified type.
It seems that achieving what you're attempting in TypeScript is not feasible, but as I understand it, this can be done in Flow instead.
In TypeScript, it's not possible to impose constraints on a generic type that expects another generic as an argument.
Here is an example of the most basic Wrap type:
type Wrapp<T> = { wrapped: T }
type Unwrap<T> = T extends Wrapp<(infer R)> ? R : never
For more information on a similar limitation, please refer to this source.
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