In Typescript, if at least one element in an array is not empty, the function should return false without utilizing iterators

My current approach involves receiving a string array and returning false if any of the elements in the array is false.

 myMethod(attrs: Array<String>) {
   for (const element of attrs) {
      if (!element) {
        return false;
      }
    }

    return true;
}

Any suggestions on simplifying this code?

Answer №1

One of the great features in Javascript is the Array method that checks if every item satisfies a predicate, known as every.

For example:

const arr = [1, 2, null];

const every = arr.every(item => item !== null); // This will return false as not every item is not-null.

A more concise way to achieve this is by casting an item to a boolean:

const every2 = arr.every(item => Boolean(item)); // This will yield false for values like 0, null, undefined, etc.

An even shorter method involves only passing a Boolean constructor to a callback, which will pass items to its constructor:

const every3 = arr.every(Boolean);

Don't forget to explore other helpful methods such as find and some.

Remember that while these built-in functions do use iteration, JavaScript handles them smoothly under the hood.

Answer №2

Give this a shot:

let items = [true, false, true];

let noFalseItems = !items.some( item => (item === false) );

console.log(noFalseItems);

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