In what way can I ensure that both parameters of a function match a particular Union type?

My goal is to develop a function that takes two parameters. The first parameter is a union type, and the second parameter's type depends on the type of the first one.

For instance:

type Fruit = "Orange" | "Apple" | "Banana";

function doubleFruit<T extends Fruit, K extends T>(fruit1: T, fruit2: K) {
   // At this point,
   // both fruit1 and fruit2 should be the same fruit
}

The following statements behave as expected

 
 // Error occurs because Orange is not the same as Apple or Banana
 doubleFruit("Orange", "Apple"); 
 doubleFruit("Orange", "Banana");

 // Runs smoothly, as both are the same fruit
 doubleFruit("Apple", "Apple");


However, when the first parameter is dynamic, there is a strange outcome

function run(x: "Orange" | "Apple") {

 // Shouldn't work since x could vary
 doubleFruit(x, "Orange");
}

It seems that due to x being either Orange or Apple, having the second parameter as Orange does not meet the requirement of both parameters being identical.

Edit: Here's my desired objective

type Fruit = "Orange" | "Apple" | "Banana";


function doubleFruit<T extends Fruit, K extends T>(fruit1: T, fruit2: K) {
  // At this point
  // both fruit1 and fruit2 should be the same fruit
}

function run(x: "Orange" | "Apple") {
  // I want this to be valid: 
  //   Regardless of the value of x, the other parameter must be the same,
  //   and therefore should be accepted
  doubleFruit(x, x); 

  // But these shouldn't be allowed: 
  //   Since x can vary, specifically passing only one of the values should not work
  doubleFruit(x, "Orange")
  doubleFruit(x, "Apple")
  
}

I am looking for a way to achieve the above-described functionality.

Answer №1

To see if this solution fits your situation, give it a try:

type Food = "Pizza" | "Pasta" | "Tacos";

function doubleFood<T extends Food, K>(food1: T, food2: K & T) {
   // In this block of code
   // both 'food1' and 'food2' must be the same type of food
}

doubleFood("Pizza", "Pasta"); 
doubleFood("Pizza", "Tacos");

doubleFood("Pasta", "Pasta");

const y: "Pizza" | "Pasta" = "Pasta";

doubleFood(y, "Pizza");

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