Include a parameter in a type alias

Utilizing a function from a library with the following type:

type QueryFetcher = (query: string, variables?: Record<string, any>) => Promise<QueryResponse> | QueryResponse;

I aim to introduce an additional argument to this type without modifying the declaration in the source file.

My approach was to create:

type WithHeader = (header: string) => Promise<QueryResponse> | QueryResponse

type QueryFetcherWithHeader = QueryFetcher & WithHeader

However, this did not result in:

(query: string, variables?: Record<string, any>, header: string) => Promise<QueryResponse> | QueryResponse;

It seems there is a misunderstanding on my part, but I am unable to pinpoint it.

typescriptfunctiontype-alias

Answer №1

When it comes to functions, the intersection type may not be the solution you're looking for. Instead, consider creating your own custom types like this:

type QueryFetcher = (query: string, variables?: Record<string, any>) => Promise<QueryResponse> | QueryResponse;

type QueryFetcherWithHeader = (query: string, variables?: Record<string, any>, header: string) => Promise<QueryResponse> | QueryResponse;

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