Instead of using `await asyncCall()`, try using `(await asyncCall())[0]`

After examining the Typescript code below, I'm curious to understand the rationale behind assigning myArray with (await asyncRPCCall())[0] instead of simply using await asyncRPCCall(). Why is the result placed inside () and why return only the first element? I'm interested in what sets this approach apart.

export class myClass {

 static async myFunction(): Promise<void> {

   const myArray: Array<Array<string>> = (await asyncRPCCall())[0]
   console.log(myArray) // returns [['a','b','c','d'],['e','f','g','h']]

 }

}

Answer №1

why is myArray being assigned with (await asyncRPCCall())[0] instead of just await asyncRPCCall()?

The reason is that asyncRPCCall is a promise, not a function that returns a promise when called.

Why are the results in parentheses?

asyncRPCCall() is a promise that resolves to an array.

The expression (await asyncRPCCall())[0] first awaits the promise, then retrieves the first item from the array.

await asyncRPCCall[0] would incorrectly treat asyncRPCCall as an array, attempt to read the first value from it, then await the promise of that value. Since asyncRPCCall is a promise, not an array, this approach would be incorrect.

and return the first element?

The code is seeking the first element from the array.

Answer №2

The individual calling probably expected to retrieve the initial component from the asynchronous response.

It appears that the function asyncRPCCall() is producing an array, and the individual simply desires the first element.

A potential solution is to store the outcome in a temporary array and then access the first element.

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