Is it necessary to validate each parameter in a typescript overload declaration?

When dealing with two overloads of update, I can differentiate between them by inspecting the first parameter:

class CRC16 {
    update(buffer: number[], offset: number, length: number): number;
    update(data: number): number;
    update(buffer: number[] | number, offset?: number, length?: number) {
        if (Array.isArray(buffer)                              // Checking first parameter
              && offset !== undefined && length !== undefined) // These checks may be unnecessary
            return length - offset;
        else
            return 1;
    }
}

const c = new CRC16();
console.log(
    c.update(1),
    c.update([1, 2, 3, 4], 1, 4));

Dealing with

error TS2532: Object is possibly 'undefined'
issues related to length and
offset</code when I remove the redundant checks from the code. (Even though typescript already disallows calling <code>c.update([1, 2, 3, 4])
due to it not matching any overload.) Is there a more succinct way to handle this without meticulously examining every parameter?

Answer №1

I find these three overloads to be quite similar and not very helpful. Also, why change a function parameter from buffer to data? If they are different, shouldn't there be two separate functions?

Do we really need all of these interfaces?

update(buffer: number[] | number, offset?: number, length?: number): number

This one covers all the previous overloads. As for skipping checks in your code, I fail to see the reasoning behind it. TypeScript may add types to your code, but it doesn't eliminate the need to check your function inputs, as you would in plain JavaScript.

It seems like you're trying to delegate too much responsibility to TypeScript.

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