Is it possible for TypeScript to perform union type assertion in this scenario?

Is it possible for TypeScript to perform a union type assertion in this scenario? I am trying to use ab.a, ab.b, or ab.hasOwnProperty to assert either type A or type B. How can I achieve this?

export interface A extends Object {
    a: string;
}

export interface B extends Object {
    b: number;
}

export type AorB = A | B;

function test(ab: AorB) {
    // Can TypeScript automatically infer this?
    if (ab.hasOwnProperty('a')) {
        ab.a // type error
    }
}

Answer №1

Revise your function according to the following instructions:

function checkType(input: AorB) {
    // Will TypeScript be able to automatically infer this?
    if ('a' in input) {
        console.log(input.a);
    }
}

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