Is it possible to activate every function within a prototype?

When presented with a class structure as demonstrated below, I am able to iterate through all its PropertyNames using console.log.

class Security {
  constructor(param: ParamType) {
    this.method1(param);
    ...
    this.methodN(param);
  }
  method1(param){...};
  ...
  methodN(param){...};
}

Object.getOwnPropertyNames(Security.prototype).forEach( (value) => {
    console.log('Method: ', value);
    // value()?
});

My query is regarding how to trigger the execution of all methods instead of leaving them as placeholders in // value()?

Answer №1

Here is an example of how you could structure your code:

class Safety {
  task1(parameter) {
    console.log("Task 1");
  }

  task2(parameter) {
    console.log("Task 2");
  }
}

function executeAll() {
  Object.getOwnPropertyNames(Safety.prototype).forEach(value => {
    if (value !== 'constructor' && typeof Safety.prototype[value] === 'function')
        this[value]();
  });
}

executeAll.apply(new Safety())

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