Is it possible to create a class object with properties directly from the constructor, without needing to cast a custom constructor signature

class __Constants__ {
  [key: string]: string;
  constructor(values: string[]) {
    values.forEach((key) => {
      this[key] = key;
    });
  }
}

const Constants = __Constants__ as {
  new <T extends readonly string[]>(values: T): { [k in T[number]]: k };
};

const __colors__ = ["BLUE", "GREEN"] as const;

const Colors = new Constants(__colors__);
// const Colors: {
//   BLUE: "BLUE",
//   GREEN: "GREEN",
// }

Is there a way to define the __Constants__ class to have the same output type as the cast, without needing to modify the custom constructor signature?

Note that I am currently working on transitioning an old JavaScript codebase to TypeScript and aiming to minimize alterations to the original JS code. The actual Constants class is more complex, but here I've simplified the issue I'm encountering.

Answer №1

Here is how it operates:

const Constants = class {
  [key: string]: string;
  constructor(values: string[]) {
    values.forEach((key) => {
      this[key] = key;
    });
  }
} as {
  new <T extends readonly string[]>(values: T): { [k in T[number]]: k };
};


const __colors__ = ["BLUE", "GREEN"] as const;

const Colors = new Constants(__colors__);

TypeScript playground

This script utilizes what are known as "Class expressions"


UPDATE: I experimented with another approach. Instead of a class, why not use a function like this:

function Constants<T extends readonly string[]>(values: T): { [k in T[number]]: k } {
  const obj: any = {};
  values.forEach((key) => {
    obj[key] = key;
  });
  return obj;
}

TypeScript playground

Remember to invoke it as a function rather than creating an instance of the class:

const __colors__ = ["BLUE", "GREEN"] as const;

const Colors = Constants(__colors__); // avoid using "new" here

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