Is it possible to create a function that only accepts a union type if it includes a specific subtype within it?

Is there a way to define the function processArray so that it can handle arrays of type string[], without explicitly mentioning individual types like type1 or type2? For instance, could we indicate this by using arr: type1 | type2?

The objective here is to avoid TypeScript errors for all four examples of function calls at the bottom. You can see how two of these result in errors on this playground link.

The motivation behind this approach is that the function will be employed in an application with numerous union types, each having the processed type as its subtype (these types are derived from an OpenAPI spec, hence they may change in the future). Rather than creating new union types for all variations or listing them as potential argument types for the function, I simply want to specify the subtype that the function operates on.

function processArray<T extends string[]>(arr: T): void {
    console.log(arr);
}

const sArr = ["a", "b", "c"];
const nArr = [1, 2, 3];
const bArr = [true, false];

const arr1 = Math.random() < 0.5 ? sArr : nArr
processArray(arr1); // error, but shouldn't be

const arr2 = Math.random() < 0.5 ? sArr : bArr
processArray(arr2); // error, but shouldn't be

const arr3 = Math.random() < 0.5 ? nArr : bArr;
processArray(arr3); // error as intended, since arr3 cannot possibly be a string array

Answer №1

In the realm of TypeScript, the constraints imposed by generics act as an upper limit on a type rather than a lower one. For instance, with T extends string[], it mandates that T must be a subtype or assignable to string[]. What is truly desired is a lower boundary where string[] can be assigned to T instead. This indicates a need for a type that can accept a string array, not exclusively provide one. Although there exists a feature request at microsoft/TypeScript#14520 advocating for this change, it has not been incorporated into the language as of yet.

Essentially, what's required here is a slightly altered constraint. The objective is to define T as an array type through T extends readonly unknown[], allowing the element type of that array to potentially be some form of a string. Rather than constraining the element type to solely a string from above or below, the aim is to establish an overlap between the type and string. Therefore, if the elements in the array encompass strings, string unions like string | boolean, specific strings like

"a" | "b" | "c"
, or even combinations like "a" | number, these should all be acceptable. Rejection would only occur if there is no intersection at all, such as with a type like number | boolean.

To express this constraint effectively, one can do so as follows:

function processArray<T extends readonly unknown[] &
    (string & T[number] extends never ? never : unknown)
>(arr: T): void {
    console.log(arr);
}

This self-referential constraint, also known as F-bounded quantification, requires that T is assignable to readonly unknown[] while simultaneously satisfying the condition specified by the intersection type representing an overlap - string & T[number]. If this overlap is non-existent, leading to the impossible never type, the conditional assessment yields the outcome of rejecting everything. Conversely, when an overlap exists, resulting in the accept-everything unknown type, the evaluation is successful.

In summary, if the element type within T can potentially include a string type, the constraint evaluates to T extends readonly unknown[], hence accepting the array. However, failure is inevitable if the element type cannot incorporate a string, causing the constraint to evaluate to T extends never.

An experiment can help demonstrate the functionality:

const sArr = ["a", "b", "c"];
const nArr = [1, 2, 3];
const bArr = [true, false];

const arr1 ...

processArray(arr3); // error

processArray(["a", "b"] as const); // okay
processArray(["a", 1] as const); // okay
processArray([1, 2] as const); // error

The test outcomes verify that arrays incapable of accommodating any type of string will indeed be rejected.

Access the Playground link to view the code snippet

Answer №2

If you're looking for a solution, consider the following code snippet:

function checkArray<T extends string | number | boolean>(arr: T[]): void {
    const [first] = arr;

    if (typeof first === "string") {
        console.log(arr); // perform some complex operations here
    } else {
        // do nothing for arrays that are not of type string[]
    }
}

This function allows flexibility with arrays containing different data types, but if you require uniformity in your application, you can use the following alternative approach (with slightly more processing overhead):

if (arr.every(value => typeof value === "string")) {

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