Consider the following code snippet:
const a = "url";
const b = "/route";
const c = a + b;
Even though TypeScript knows the exact values of a and b, resulting in immutable constants, when concatenating both strings, the type of c is displayed as a generic string.
Is there a way for c to display url/route instead?
https://i.stack.imgur.com/mK6OO.png https://i.stack.imgur.com/jcwfi.png
To determine the literal type, an additional function for concatenation is required:
const a = "name";
const b = "/path";
const c = a + b;
const concatenate = <
A extends string,
B extends string
>(a: A, b: B): `${A}${B}` => `${a}${b}`
const output = concatenate(a, b) // "name/path"
In order to ensure safe type inference in this scenario, refrain from using + (plus) for string concatenation.
During runtime, the variable c is dynamically changing. If you check the log output, you will see that c's value is "URL/route". However, when hovering over c with the cursor before the code has finished processing, it may not reflect the updated value and instead display the data type of the variable.
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