Is it possible to eliminate additional properties from an object using "as" in Typescript?

I am looking for a way to send an object through JSON that implements an interface, but also contains additional properties that I do not want to include. How can I filter out everything except the interface properties so that only a pure object is sent?

For example:

interface IBlock{
  x:number;
  y:number;
}

class Block implements IBlock{
  public z:number;
}
...
send(JSON.stringify(new Block() as IBlock));

desiredResponse = "{x:0,y:0}";
receivedResponse = "{x:0,y:0,z:0}";

Answer №1

Interfaces and casting with the `as` keyword are tools used during compilation that have no impact on the code's execution at runtime.

An alternative approach would be to utilize the `pick` method from the `lodash` library:

const subset = _.pick(obj, ['x', 'y'])

If you prefer not to use an external library, destructuring can achieve the same result:

const subset = (({ x, y }) => ({ x, y }))(obj);

A more advanced technique involves utilizing actual classes with `reflect-metadata` and decorators to make dynamic decisions about the code's behavior during runtime.

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