Is it possible to indicate the base type for a generic function?

Is it possible to define the generic type T as an Object rather than a primitive type like number or string?

For example, this clone function should only accept Objects as input. It will destructure the input object o, set its prototype back to that of the original Object, and then return the new object.

export function clone<T>(o: T): T {
  return Object.setPrototypeOf({ ...o }, o.constructor.prototype);
}

The linter is indicating the following error:

Property 'constructor' does not exist on type 'T'

Answer №1

The object type (noting the lowercase o) was specifically created to encompass "non-primitive" types; in essence, object is the opposite of

string | number | bigint | boolean | symbol | undefined | null
.

Do not mistake it for Object (with an uppercase O), which refers to anything that can be indexed like an object and essentially complements of undefined | null. For example, a string such as "foo" has an apparent method like toUpperCase(); calling "foo".toUpperCase() wraps "foo" in a String object. If excluding primitives like string, you should use object instead of Object.

In any case, this means that the call signature of clone() should appear as follows:

export function clone<T extends object>(o: T): T {
  return Object.setPrototypeOf({ ...o }, o.constructor.prototype);
}

By restricting the type parameter T to object, only non-primitive parameters for o will be allowed:

clone(new Date()); // valid
clone({ a: 1, b: 2 }); // valid
clone([1, 2, 3]); // valid
clone("oops"); // invalid
clone(123); // invalid
clone(false); // invalid
clone(Symbol("wha")); // invalid
clone(undefined); // invalid
clone(null); // invalid

Link to playground with code

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