Is it possible to overlook specific attributes when constructing an object using TypeScript interfaces?

I have defined an interface with various properties. I am looking to instantiate an object based on this interface, but I only want to partially initialize some of the properties. Is there a way to accomplish this? Thank you.

export interface Campaign {
  id: string;
  name: string;
  createdOn: string;
  lastUpdated: string;
  createdBy: User;
  type: CampaignType;
  status: CampaignStatus;
  startDate: string;
  endDate: string;
  budget: number;
  description: string;
  account: Account;
}

I am attempting to create an array of campaign objects like so:

let campaigns: Campaign[] = [
    {  id: "1",
       name: "test campaign"
      }
   ];

However, I encounter the following error:

Type '{ id: string; name: string; }' is missing the following properties from type 'Campaign': createdOn, lastUpdated, createdBy, type, and 6 more.ts(2740)

Answer №1

try utilizing Partial -

let items: Partial<Item>[] = [
    {  id:"1",
       name: "example item"
      }

   ];

Answer №2

By setting the optional properties to be nullable, everything should function properly.

For example:

type Person = {
  name: string;
  age?: number;
};

// We can provide a value for the "age" property
let sam: Person = { name: "Sam", age: 25 };

// ... or we can specifically assign the value as null
let sue: Person = { name: "Sue", age: null };

// ... or we can simply omit the property altogether
let max: Person = { name: "Max" };

Answer №3

To make properties optional and not set a value upon creation, you can designate them as optional by using the syntax { propName?: propType }

If you want all properties to be optional, you can utilize the Partial keyword like this:

Partial<{
  prop1: string,
  prop2: number,
}>

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