Is it possible to refine a tuple through the type of another tuple?

Is it possible to refine tuples based on type checks similar to how null checks can be refined using === null? I am trying to figure this out but haven't had any success so far. Here is a link to the TypeScript playground.

// refining against null works
declare function fooA(): [string, null] | [null, string];
function A() {
    const x = fooA();

    if (x[0] === null) {
        const y = x[1]; // y = string
    }
}

// attempting to refine based on type = string, fails
declare function isString(x: any): x is string;
declare function fooB(): [string, number] | [number, string];
function B() {
    const x = fooB();

    if (isString(x[0])) {
        const y = x[1]; // y = string | number
    }
}

Answer №1

There is a specific design limitation in place here. While you are able to utilize values such as null for distinguishing between union members and potentially narrowing the type, it is not possible to achieve this using type guards. For further insights on this topic, check out this relevant TypeScript issue (even though it focuses on objects rather than tuples, the principle remains the same).

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