Is it possible to surpass the limits of Typescript generic types?

Imagine having a function with intricate types

function torgle<
    A extends string, 
    B extends number, 
    Flurg extends string = `[${A}]<>[${B}]`
>(flurg: Flurg): string {
    return `hello, ${String(flurg).replace(/[[\]<>]/g, '')}`
}

Usually, the type Flurg is not predefined, so it's easier to let torgle create it:

torgle<'blue', 32>('[blue]<>[32]')
hello, blue32

However, there are times when I have a custom Flurg type and want to pass it in myself:

>> torgle<'_unused', '_unused', 'cheeseburger'>('cheeseburger')
hello, cheeseburger

In such cases, having A and 

B</code becomes unnecessary. It would be more efficient to have a variant of <code>torgle
where they are not obligatory:

function torgle<Flurg extends string>(flurg: Flurg) { ... }

Refer to this CodeSandbox example.

Is there a way to mix these two versions of torgle, or do I need separate functions like torgle1 and torgle2?

javascripttypescriptgenericsoverloading

Answer №1

Typescript allows you to utilize Template Literal Types using strings, enabling you to do the following:

type Flurg = `[${string}]<>[${number}]` | string;
function torgle(flurg: Flurg): string {
  return `hello, ${String(flurg).replace(/[[\]<>]/g, '')}`
}
console.log(torgle('[blue]<>[32]')); // hello, blue32
console.log(torgle('cheeseburger')); // hello, cheeseburger

This approach also eliminates Generics from your code (which can be a bit more challenging to grasp initially).

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