Consider having two distinct interfaces:
interface InterfaceOne {
myString: string,
myNum: number
}
interface interfaceTwo extends InterfaceOne {
myBool: boolean
}
Utilizing the TypeScript code below:
let somedata: interfaceTwo = {
myString: "hello world",
myNum: 42,
myBool: false
Is there a method to transform somedata into an InterfaceOne, while eliminating the myBool property from the object?
Yes, it is possible to achieve what you want, but not in the way you currently have it implemented. The issue lies in hardcoding InterfaceTwo into your code. If you simply remove myBool from the data structure, it will not automatically become InterfaceOne as that is not how Object Oriented Programming works. Instead, you will encounter an error. To make your variable capable of holding values of either A or B, avoid extending and simply use both interfaces.
interface InterfaceOne {
myString: string,
myNum: number
}
interface InterfaceTwo {
myBool: boolean
}
let someData: InterfaceOne | InterfaceTwo = {
myString: "hello world",
myNum: 42
}
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