Is it possible to turn off the differentiation between null and undefined in TypeScript strict null-checking mode?

I've been in the process of upgrading a large TypeScript codebase to enforce strict null-checks. This codebase contains numerous types with optional properties:

interface MyInterface {
  member1?: number;
  member2?: string;
}

Additionally, it defines a type Nullable<T> = T | null and includes numerous return null statements.

Now, I'm encountering numerous compiler errors that highlight the inability to convert T | null to T | undefined, and vice versa. For example:

interface MyInterface {
  member1?: number;
  member2?: string;
}

const myFunction = () => {
  return null;
}

const item: MyInterface = {};
item.member1 = myFunction();      // <== cannot assign null to undefined

While I appreciate the benefits of strict null-checking in TypeScript, I find the distinction between null and undefined unnecessary in this project. The functions that return null essentially return nothing - the specific value (null or undefined) is irrelevant. The same applies to the optional properties - they are either assigned a value or remain undefined.

Furthermore, I prefer not to convert member1?: number; to member1: Nullable<number>;, or modify the existing return null statements.

Is there a way to disable the distinction between null and undefined, at least in TypeScript?

Answer №1

Instead of composing a comment, I have decided to provide a code example in the form of an answer.

If I were in your shoes, I would consider adding a wrapper for all your interfaces with optional (weak) properties.

Here is an illustration of such a wrapper:


type MapNullable<T> = {
    [P in keyof T]: undefined extends T[P] ? (T[P] | null) : T[P]
}

interface MyInterface {
  member1?: number;
  member2?: string;
}

const myFunction = () => {
  return null;
}

const item: MapNullable<MyInterface> = {};
item.member1 = myFunction(); // member1?: number | null | undefined

The MapNullable function iterates through all properties. For optional properties, it extends them with the additional type of null; for non-optional properties, it leaves them unchanged.

While this may not be the most optimal solution, it can assist you during the migration process.

Once you have completed the migration, you can refine your types and eliminate the need for the MapNullable interface.

Although MapNullable might not be the most descriptive name for this type, it is still preferable to generic names like Foo or Bar.

I echo @jcalz's sentiments – I can't envision a different approach to handling undefined or null values.

UPDATE

Fortunately, your code appears to be functioning without any errors in the TypeScript playground. You can view the functional code here.

I have disabled strictNullChecks, and there are no errors present.

Remember to explicitly define the return type of your function.

const myFunction = ():null => {
  return null;
}

TypeScript version: 4.0.2

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