Is it possible to verify if an object matches a type without explicitly setting it as that type?

In order to illustrate my point, I believe the most effective method would be to provide a code snippet:

type ObjectType = {
  [property: string]: any
}

const exampleObject: ObjectType = {
  key1: 1,
  key2: 'sample'
}

type ExampleType = typeof exampleObject;

The type ExampleType is currently equivalent to ObjectType, but my goal is for it to reflect the specific type of the object. However, I still want the object exampleObject to conform to ObjectType.

Is there a solution to achieve this?

Answer â„–1

UPDATE FOR TS4.9+

Exciting news for TypeScript 4.9 and beyond—introducing the new `satisfies` operator. This operator allows you to contextually check a value against a type without actually assigning it that type, eliminating the need for a helper function. Here's how it works:

const x = {
  a: 1,
  b: 'test'
} satisfies ObjType // no problem here

type XType = typeof x;
/* type XType = {
    a: number;
    b: string;
} */

const oops = 123 satisfies ObjType; // error!

Check out this Playground link for code


PREVIOUS ANSWER FOR TS4.8-

To deal with TypeScript versions prior to 4.9, you can utilize a workaround by creating a generic helper function as shown below:

const asObjType = <T extends ObjType>(t: T) => t;

The `asObjType` function returns its input `t` without altering the type `T`, which is constrained to `ObjType`. Instead of explicitly annotating `x` as `ObjType`, you assign the output of `asObjType` to it. Let's see this in practice:

const x = asObjType({
  a: 1,
  b: 'test'
});

type XType = typeof x;
/* type XType = {
    a: number;
    b: string;
} */

Everything seems to be working smoothly. Additionally, the function blocks non-`ObjType` values from passing through:

const oops = asObjType(123); // error!
// ------------------> ~~~
// Argument of type 'number' is not assignable to parameter of type 'ObjType'

All good on that front.

Explore the code further on the Playground

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