In my constructor, I am currently following this approach:
this.articleSlug = _route.url._value[1].path;
However, TypeScript throws an error:
Property "_value" is not found on type Observable<Params>
Is there a more efficient way to achieve this? I am working with Angular 4 using TypeScript and webpack.
This is specifically for when I utilize _route: ActivatedRoute in my constructor.
To access the route information, you must first subscribe to the route and use a callback function to extract it. Here is an example:
_route.url.subscribe(values: UrlSegment[] -> /* access url segments from values array */)
// Alternatively, if you require URL parameters
_route.params.subscribe(params: Params -> console.log(params['paramName']));
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