Is there a way to convert a literal type from the type level to the term level in TypeScript?

Consider this scenario: I have created a type that can only hold one specific value:

  export type IfEqual<T, U> =                                                                               
    (<G>() => G extends T ? 1 : 2) extends                                                                                                        
    (<G>() => G extends U ? 1 : 2) ? true : false;     

By using the following declaration, I am able to assign values a, which will always be true, and b, which will always be "foo".

  declare const a: IfEqual<'a', 'a'>;     // automatically set as true                                                                                                              
  declare const b: IfEqual<'a', 'a'> extends true ? "foo" : "bar";  // resolved as "foo"

Given that the type has only one possible value, I wonder if there's a way to directly convert that type into its corresponding value.

Answer №1

"Is there a way to directly transform that type into its corresponding value?"

Unfortunately, no.

Typescript only exists during compilation. Once the code is compiled and executed, all type information is discarded. What remains is the plain javascript that is actually run.

In fact, if you input your code into the typescript playground, you'll notice that the right-hand pane is completely empty. All the types have vanished.

Typescript does not handle any actual computation or logic for you. Instead, it ensures that the logic and computations you write adhere to the defined types in your codebase.

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