Is there a way to determine the type of an example without having to export it?

Let's say I have an object with example data:

const responseData = {
  "results": [{
    "id": 1,
    "name": "Alice"
    },
    {
    "id": 2,
    "name": "Bob"
    }
  ]
}

To extract the type of this object, we can do the following:

type ResponseType = typeof responseData;

The issue is that when compiling the .ts file, the example data is unnecessarily exported as well.

I only require the type information during compile time and don't need the actual example data. Is there a solution to avoid exporting the example data?

Answer №1

Is there a way to only use the example type at compile time and then discard it?

Unfortunately, no. If you are receiving this content as JSON, you can consider using tools such as JSON to DTS to convert your JSON into TypeScript declarations.

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