Is there a way to dynamically define the return type of a function in Typescript?

Can the variable baz be dynamically assigned the string type?

type sampleType = () => ReturnType<sampleType>; // Want to return the type of any function I pass (Eg. ReturnType<typeof foo>)

interface ISampleInterface {
  baz: sampleType;
}

function foo(): string {
  return 'AAAAAAA';
}
const foobaz = {
  baz: foo,
} as ISampleInterface;

const qux = foobaz.baz();

qux; // Qux has type "any"

Answer №1

The purpose of the interface is not clear to me. Here is a revised version that better aligns with what I believe you are aiming for:

interface ICustomInterface<T extends () => any> {
  customFunction: () => ReturnType<T>;
}

function sampleFunction(): string {
  return 'AAAAAAA';
}
const customObj: ICustomInterface<typeof sampleFunction> = {
  customFunction: sampleFunction,
}

const result = customObj.customFunction();

If generic inference was possible, the typeof sampleFunction part would be unnecessary.

Answer №2

It seems like you're putting in a lot of effort. TypeScript actually has a feature called type inference that can handle this for you automatically. Just remove the as IExampleInterface and everything should work smoothly

function foo(): string {
  return 'AAAAAAA';
}
const foobar = {
  bar: foo,
}

const baz = foobar.bar();

baz; // The type of Baz is now "string"

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