After subscribing to my observable with RxJS, I am looking to introduce an additional delay before running part of my logic. While I am aware of the finalize operator and how it can be used within a pipe, I would like to avoid immediate execution after the completion of the observable.
Is there a way to incorporate a delay before the finalize operator is executed?
Some context:
The observable I am subscribing to involves a server call, so I am only anticipating one value to be returned.
Sorry, it is not possible to introduce a delay before the finalize function.
One workaround is to use a timer in conjunction with finalize.
It's important to note that using this method is perfectly safe and not considered an anti-pattern. The finalize function will only be executed once, after the source observable has emitted all its values and completed.
Take a look at this example:
of([1,2,3])
.pipe(
finalize(() => {
timer(1000).subscribe(() => {/* Code executed after 1 second delay */})
})
)
.subscribe(value => {
console.log(value);
})
To introduce a delay in the execution, simply utilize the delay operator within a pipe.
Observable.pipe(delay(200))...
For more information and resources, visit: https://rxjs-dev.firebaseapp.com/api/operators/delay
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