Is there a way to verify within the "if" statement without repeating the code?

Is there a way in javascript (or typescript) to prevent redundant object rewriting within an if statement condition?

For example:

if (A != null || A != B) {
 // do something here
}

// can it be done like this:
if (A != null || != B) { // avoid repeating "A" here
// do something here
}

Does anyone have suggestions or any other questions related to this topic?

Answer №1

Consider the following approach:

if([B, null].includes(A)) {
   // ...
}

Answer №2

When dealing with if conditions, there isn't a predefined shortcut available. If you find yourself working with a complicated expression like A and wish to sidestep rewriting it, the common approach is to use a temporary variable:

if ( (temp=A) != null || temp != B ) {

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