JavaScript => Compare elements in an array based on their respective dates

I have an array consisting of more than 50 objects. This array is created by concatenating two arrays together. Each object in this array contains a 'date' key with the date string formatted as:

`"2017-03-31T11:30:00.000Z"`

Additionally, there is a 'caption' key with text associated with each object. Here's an example of elements within the array:

[
    {date: "2017-03-31T11:30:00.000Z", caption: "text_1"},
    {date: "2016-03-31T11:30:00.000Z", caption: "text_2"},
    {date: "2016-03-31T11:30:00.000Z", caption: "text_3"},
    {date: "2017-03-31T11:30:00.000Z", caption: "text_4"}
]

In Ruby, a language I am more familiar with, you can map elements in an array and return a new one based on conditions from if statements. I'm curious if JavaScript has similar functionality. Currently, I am iterating through the array and comparing each element to others, but I know this may not be the most efficient way. Ideally, I would like to achieve something like:

let newArray = myArray.map((a, b) => { if (a.date === b.date) { return {text1: a.caption, text2: b.caption}}});

The desired result would look like:

[
  {text1: "text_1", text2: "text_4"},
  {text1: "text_2", text2: "text_3"}
]

Is there a more elegant and efficient way to accomplish this in JavaScript?

Thank you for your help.

Answer №1

After careful consideration, it appears that achieving the desired functionality in JavaScript may not be as straightforward or elegant as hoped for (uncertain about efficiency).

To address your specific scenario, a potential solution could involve creating a new object that utilizes dates as keys and stores various captions, followed by converting this object into an array:

const aggregated = {};

myData.forEach((item) => {
    if (item.date in aggregated) {
        aggregated[item.date].description2 = item.caption;
    } else {
        aggregated[item.date] = { description1: item.caption };
    }
});

const updatedArray = Object.keys(aggregated).map(date => aggregated[date]);

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