If I have an object called userData = {..}
and I need to create another object, userDataB, with properties a, b, c, and d from userData but only if they are defined. One way to achieve this is by using the following approach:
userDataB = {}
if(userData.a){userDataB.a = a};
if(userData.b){userDataB.b = b};
...
Is there a cleaner way to accomplish this task, perhaps leveraging ES5 or ES6 features?
Here's another helpful tip:
const object1 = {
a: 'string',
b: 42,
c: true,
d: undefined
};
let object2 = Object.assign(
...Object.keys(object1).map(key =>
object1[key] !== undefined ? { [key]: object1[key] } : {}
)
);
Try this as well:
let object2 = Object.assign(
...Object.entries(object1).map(obj =>
obj[1] !== undefined ? { [obj[0]]: obj[1] } : {}
)
);
And consider this option too:
let object2 = Object.entries(object1).reduce(
(acc, val) => (val[1] !== undefined ? Object.assign(acc, { [val[0]]: val[1] }) : acc),
{}
);
Utilize `JSON` methods to automatically remove any `undefined` properties:
var data = {
x: "x",
y: true,
z: undefined,
w: 5
};
var newData = JSON.parse(JSON.stringify(data));
console.log(newData);Simply utilize Object.assign() to duplicate it into a fresh object:
var data = {
x: 10,
y: 20,
z: 30
}
dataCopy = Object.assign({}, data);
console.log(dataCopy);When dealing with undefined or null values:
var data = {
x: 100,
y: null,
z: undefined,
w: 400,
v: 500
}
var dataCopy = Object.assign({}, data);
Object.keys(dataCopy).forEach((key) => (dataCopy[key] == null) && delete dataCopy[key])
console.log(dataCopy);If you have a specific situation, this code snippet could be helpful:
const filteredObject = Object.keys(originalObject).reduce((result, key) => {
if(originalObject[key] != undefined){ // customize this condition
result[key] = originalObject[key];
}
return result;
},{});
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